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288n^2-392=0
a = 288; b = 0; c = -392;
Δ = b2-4ac
Δ = 02-4·288·(-392)
Δ = 451584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{451584}=672$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-672}{2*288}=\frac{-672}{576} =-1+1/6 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+672}{2*288}=\frac{672}{576} =1+1/6 $
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